Question
The path of a firework is described by the function: h(1) = 4.97? + 491 + 1.5
where h(t) is the height of the firework, in meters, and t is the time in seconds since the launch.
Determine the maximum height of the firework. Show work
where h(t) is the height of the firework, in meters, and t is the time in seconds since the launch.
Determine the maximum height of the firework. Show work
Answers
To find the maximum height of the firework, we need to find the vertex of the function.
The vertex of the function h(t) = a(t-b)^2 + c is (b,c), where b is the x-coordinate of the vertex, and c is the y-coordinate of the vertex.
In this case, h(1) = 4.97(1)^2 + 491(1) + 1.5 = 497.47 meters.
So, the vertex is (1, 497.47).
Therefore, the maximum height of the firework is 497.47 meters.
The vertex of the function h(t) = a(t-b)^2 + c is (b,c), where b is the x-coordinate of the vertex, and c is the y-coordinate of the vertex.
In this case, h(1) = 4.97(1)^2 + 491(1) + 1.5 = 497.47 meters.
So, the vertex is (1, 497.47).
Therefore, the maximum height of the firework is 497.47 meters.
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