Question
A company manufactures cylindrical cans. Each can has a volume of 9p cubic centimetres and a height of 4 centimetres. The diameter of the can is 3. use 3.14 as pi. The company plans to manufacture a can with a volume that is 25% larger than
the original can. What is the radius of the new can if the height remains the same?
Round your answer to the nearest tenth.
the original can. What is the radius of the new can if the height remains the same?
Round your answer to the nearest tenth.
Answers
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The original can has a diameter of 3 cm, so it has a radius of 1.5 cm.
The volume of the original can is 9p cubic cm, which means its radius cubed is 2p.
To increase the volume by 25%, we can multiply the radius cubed by 1.25:
2p * 1.25 = 2.5p
Now we solve for the new radius by taking the cube root of 2.5p and rounding to the nearest tenth:
radius = (2.5p)^(1/3) ≈ 1.4 cm.
The volume of the original can is 9p cubic cm, which means its radius cubed is 2p.
To increase the volume by 25%, we can multiply the radius cubed by 1.25:
2p * 1.25 = 2.5p
Now we solve for the new radius by taking the cube root of 2.5p and rounding to the nearest tenth:
radius = (2.5p)^(1/3) ≈ 1.4 cm.