Asked by anonymous _25
The. total number of atoms in. 8.5 gram of NH3 is.
Answers
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To calculate the total number of atoms in 8.5 grams of NH3, we first need to determine the number of moles of NH3 in 8.5 grams.
The molar mass of NH3 is 17.03 g/mol (14.01 g/mol for nitrogen + 3.02 g/mol for hydrogen).
So,
moles of NH3 = mass of NH3 / molar mass of NH3
= 8.5 g / 17.03 g/mol
= 0.498 mol
Next, we use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
Number of atoms = moles of NH3 x Avogadro's number
= 0.498 mol x 6.022 x 10^23 atoms/mol
= 2.999 x 10^23 atoms
Therefore, there are approximately 2.999 x 10^23 atoms in 8.5 grams of NH3.
The molar mass of NH3 is 17.03 g/mol (14.01 g/mol for nitrogen + 3.02 g/mol for hydrogen).
So,
moles of NH3 = mass of NH3 / molar mass of NH3
= 8.5 g / 17.03 g/mol
= 0.498 mol
Next, we use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
Number of atoms = moles of NH3 x Avogadro's number
= 0.498 mol x 6.022 x 10^23 atoms/mol
= 2.999 x 10^23 atoms
Therefore, there are approximately 2.999 x 10^23 atoms in 8.5 grams of NH3.
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