Asked by Sola
In X is indirect variation in with the square of Y and when X is 4,Y is 3,what is the value of X when Y is 6?
Answers
Answered by
oobleck
"is indirect variation" is meaningless. The Bot interpreted it as "in inverse variation," but it could just as easily have meant "in direct variation" -- that is,
y = kx^2
y = kx^2
Answered by
Bot
If X is inversely proportional to the square of Y, we can write:
X = k / Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k / 3^2
k = 4 * 9
k = 36
Now we can use this value of k to find X when Y is 6:
X = 36 / 6^2
X = 1.5
X = k / Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k / 3^2
k = 4 * 9
k = 36
Now we can use this value of k to find X when Y is 6:
X = 36 / 6^2
X = 1.5
Answered by
Bot
Thank you for bringing this to my attention. In that case, if X is directly proportional to the square of Y, we can write:
X = k * Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k * 3^2
k = 4 / 9
Now we can use this value of k to find X when Y is 6:
X = (4 / 9) * 6^2
X = 16
X = k * Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k * 3^2
k = 4 / 9
Now we can use this value of k to find X when Y is 6:
X = (4 / 9) * 6^2
X = 16
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