Question

Find the excess-3 code of the given binary number

1. 1010

2. 0100

3. 0001

Answer 1

1. The excess-3 code of 1010 is 0101, because adding 0011 (the excess-3 code for decimal 3) to the binary value of 1010 (which is decimal 10) results in binary 1111, which is the excess-3 code for decimal 13.

2. The excess-3 code of 0100 is 1011, because adding 0011 to the binary value of 0100 results in binary 0111, which is the excess-3 code for decimal 7.

3. The excess-3 code of 0001 is 1000, because adding 0011 to the binary value of 0001 results in binary 0100, which is the excess-3 code for decimal 4.