Asked by Anonymous
If the output saturation voltage of the op-amp is ± 13V, determine Voutpp in inverting amplifier.
ACL = -40
ACL in dB = 32.0dB
RA = 500Ω
RC = 20KΩ
VIN = 0.5 Vpp
ACL = -40
ACL in dB = 32.0dB
RA = 500Ω
RC = 20KΩ
VIN = 0.5 Vpp
Answers
Answered by
Anonymous
Describe the output voltage.
Answered by
Bot
First, we need to calculate the maximum output voltage that the op-amp can produce before reaching the saturation limit:
Vsat = ±13V
Next, we need to calculate the gain of the inverting amplifier:
G = -RC/RA = -40
We can convert this to dB to find the voltage gain in decibels:
GdB = 20*log10(G) = 32.0dB
Now we can find the output voltage for a given input voltage:
Voutpp = Vin*G = 0.5*G = 0.5*(-40) = -20Vpp
However, this exceeds the op-amp's saturation limit, so the maximum output voltage will be limited to:
Voutpp_max = Vsat/G = 13/40 = 0.325Vpp
Therefore, the maximum output voltage of the inverting amplifier is 0.325Vpp.
Vsat = ±13V
Next, we need to calculate the gain of the inverting amplifier:
G = -RC/RA = -40
We can convert this to dB to find the voltage gain in decibels:
GdB = 20*log10(G) = 32.0dB
Now we can find the output voltage for a given input voltage:
Voutpp = Vin*G = 0.5*G = 0.5*(-40) = -20Vpp
However, this exceeds the op-amp's saturation limit, so the maximum output voltage will be limited to:
Voutpp_max = Vsat/G = 13/40 = 0.325Vpp
Therefore, the maximum output voltage of the inverting amplifier is 0.325Vpp.
Answered by
Bot
The output voltage of the inverting amplifier will vary linearly with the input voltage, but with a negative gain (amplification factor) determined by the ratio of the feedback resistor (RF) to the input resistor (RIN). In this case, the gain is -40, so for a given input voltage amplitude, the output voltage amplitude will be 40 times smaller. However, in practical situations, the output voltage may be limited by the saturation voltage of the op-amp if the input signal is too large. In this case, the maximum output voltage is limited to ±13V.
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