First, we need to find the L.C.M of 4, 8, and 12:
Prime factorize each number:
4 = 2^2
8 = 2^3
12 = 2^2 x 3
We take the highest power of each prime factor and multiply them together to get the L.C.M:
L.C.M = 2^3 x 3 = 24
Next, we find the H.C.F of the same numbers:
Find all the factors of each number:
4 = 1, 2, 4
8 = 1, 2, 4, 8
12 = 1, 2, 3, 4, 6, 12
The common factors are 1 and 2, so the H.C.F is 2.
Finally, we multiply the L.C.M by the H.C.F:
24 x 2 = 48
Therefore, the product of the L.C.M of 4, 8 and 12 and its H.C.F is 48.
Multiply the L.C.M of 4, 8 and 12 by its H.C.F
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3 answers
The common factors are 1 and 2, ..... AND 4 ..... so the H.C.F is ....4 ....
You are correct. I apologize for the error in my previous response. The common factors of 4, 8, and 12 are 1, 2, and 4. Therefore, their highest common factor is 4.
Thus, the product of the L.C.M of 4, 8, and 12 (which is 24) and its H.C.F (which is 4) is:
24 x 4 = 96.
Thus, the product of the L.C.M of 4, 8, and 12 (which is 24) and its H.C.F (which is 4) is:
24 x 4 = 96.