Question
Factor completely 2x2 + 4x - 2.
Answers
Answered by
oobleck
wrong yet again!
(x + 1)(x - 1) = x^2 - 1
(x + 1)(x - 1) = x^2 - 1
Answered by
Bot
First, factor out the greatest common factor of 2:
2(x^2 + 2x - 1)
Then, we need to factor the quadratic trinomial inside the parentheses.
Using the AC method, we need to find two numbers that multiply to give -1 and add to give 2. Those numbers are 1 and -1.
So, we can rewrite the quadratic trinomial as:
x^2 + 2x - 1 = (x + 1)(x - 1)
Therefore, the entire expression can be factored as:
2(x + 1)(x - 1)
2(x^2 + 2x - 1)
Then, we need to factor the quadratic trinomial inside the parentheses.
Using the AC method, we need to find two numbers that multiply to give -1 and add to give 2. Those numbers are 1 and -1.
So, we can rewrite the quadratic trinomial as:
x^2 + 2x - 1 = (x + 1)(x - 1)
Therefore, the entire expression can be factored as:
2(x + 1)(x - 1)
Answered by
Bot
You are correct, and I apologize for the mistake in my previous response.
Using the same factoring techniques as before, we can first factor out the greatest common factor of 2:
2(x^2 + 2x - 1)
Then, we can factor the quadratic trinomial inside the parentheses using the AC method. We need to find two numbers that multiply to give -1 and add to give 2. Those numbers are 1 and -1.
So, we can rewrite the quadratic trinomial as:
x^2 + 2x - 1 = (x + 1)(x - 1)
Therefore, the entire expression can be factored as:
2(x + 1)(x - 1) = 2(x^2 - 1) = 2(x + 1)(x - 1)
Using the same factoring techniques as before, we can first factor out the greatest common factor of 2:
2(x^2 + 2x - 1)
Then, we can factor the quadratic trinomial inside the parentheses using the AC method. We need to find two numbers that multiply to give -1 and add to give 2. Those numbers are 1 and -1.
So, we can rewrite the quadratic trinomial as:
x^2 + 2x - 1 = (x + 1)(x - 1)
Therefore, the entire expression can be factored as:
2(x + 1)(x - 1) = 2(x^2 - 1) = 2(x + 1)(x - 1)
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