What is the molarity of a solution Containing 72.06 grams of BaCl2 in enough water to make 800 ml of solution.

Answer 1

To calculate the molarity of the solution, first calculate the number of moles of BaCl2 present in the solution:

Number of moles = Mass ÷ Molar mass

The molar mass of BaCl2 is 137.33 g/mol (137.33 = 2x(35.45) + 137.33 = 1x(137.33))

Number of moles of BaCl2 = 72.06 g ÷ 137.33 g/mol = 0.5246 moles

Next, calculate the volume of the solution in liters:

Volume of solution = 800 ml ÷ 1000 ml/L = 0.8 L

Finally, calculate the molarity of the solution:

Molarity = Number of moles ÷ Volume of solution

Molarity = 0.5246 moles ÷ 0.8 L = 0.65575 M or 0.656 M (rounded to three significant figures)