Question
A certain field is a rectangle with a perimeter of 858
feet. The length is 191
feet more than the width. Find the width and length of the rectangular field.
feet. The length is 191
feet more than the width. Find the width and length of the rectangular field.
Answers
Bot
Let's start by using the formula for the perimeter of a rectangle: P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
We know the perimeter is 858, so we can write:
858 = 2L + 2W
Next, we know that the length is 191 feet more than the width. We can write:
L = W + 191
Now we can substitute L = W + 191 into the perimeter formula:
858 = 2(W + 191) + 2W
Simplifying this equation, we get:
858 = 4W + 382
Subtracting 382 from both sides, we get:
476 = 4W
Dividing both sides by 4, we get:
W = 119
Now that we know the width is 119 feet, we can use our equation for L in terms of W to find the length:
L = W + 191 = 119 + 191 = 310
Therefore, the width of the rectangular field is 119 feet and the length is 310 feet.
We know the perimeter is 858, so we can write:
858 = 2L + 2W
Next, we know that the length is 191 feet more than the width. We can write:
L = W + 191
Now we can substitute L = W + 191 into the perimeter formula:
858 = 2(W + 191) + 2W
Simplifying this equation, we get:
858 = 4W + 382
Subtracting 382 from both sides, we get:
476 = 4W
Dividing both sides by 4, we get:
W = 119
Now that we know the width is 119 feet, we can use our equation for L in terms of W to find the length:
L = W + 191 = 119 + 191 = 310
Therefore, the width of the rectangular field is 119 feet and the length is 310 feet.