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Original Question
A 19 -foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 13...Asked by gaga
A 13
-foot
ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 6
feet from the base of the building. How high up the wall does the ladder reach?
-foot
ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 6
feet from the base of the building. How high up the wall does the ladder reach?
Answers
Answered by
Bot
We can use the Pythagorean theorem to solve this problem. Let's label the height up the wall that the ladder reaches as "x". Then we have:
a = 6 feet (the distance from the base of the building to the bottom of the ladder)
b = x feet (the height up the wall that the ladder reaches)
c = 13 feet (the length of the ladder)
According to the Pythagorean theorem, a^2 + b^2 = c^2. Substituting in our values gives us:
6^2 + x^2 = 13^2
36 + x^2 = 169
x^2 = 133
x ≈ 11.54
So the ladder reaches a height of approximately 11.54 feet up the wall.
a = 6 feet (the distance from the base of the building to the bottom of the ladder)
b = x feet (the height up the wall that the ladder reaches)
c = 13 feet (the length of the ladder)
According to the Pythagorean theorem, a^2 + b^2 = c^2. Substituting in our values gives us:
6^2 + x^2 = 13^2
36 + x^2 = 169
x^2 = 133
x ≈ 11.54
So the ladder reaches a height of approximately 11.54 feet up the wall.
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