Question

8.00 gram of calcium chloride. Is dissolved in 1.000kg of Water. How many moles of calcium chloride are in solution? How many moons of water? Are present.

Answers

To calculate the number of moles of calcium chloride, we need to use its molar mass. The molar mass of calcium chloride is:

CaCl2 = 1 x 40.08 g/mol (for calcium) + 2 x 35.45 g/mol (for chlorine) = 110.98 g/mol

So, the number of moles of calcium chloride in 8.00 g is:

n = m/M = 8.00 g /110.98 g/mol = 0.072 mol

To calculate the number of moles of water, we can use its molar mass, which is:

H2O = 2 x 1.01 g/mol (for hydrogen) + 1 x 16.00 g/mol (for oxygen) = 18.02 g/mol

The mass of 1.000 kg of water is:

m = 1.000 kg x 1000 g/kg = 1000 g

So, the number of moles of water is:

n = m/M = 1000 g / 18.02 g/mol = 55.49 mol

Therefore, there are 0.072 moles of calcium chloride and 55.49 moles of water present in the solution.

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