Question
8.00 gram of calcium chloride. Is dissolved in 1.000kg of Water. How many moles of calcium chloride are in solution? How many moons of water? Are present.
Answers
To calculate the number of moles of calcium chloride, we need to use its molar mass. The molar mass of calcium chloride is:
CaCl2 = 1 x 40.08 g/mol (for calcium) + 2 x 35.45 g/mol (for chlorine) = 110.98 g/mol
So, the number of moles of calcium chloride in 8.00 g is:
n = m/M = 8.00 g /110.98 g/mol = 0.072 mol
To calculate the number of moles of water, we can use its molar mass, which is:
H2O = 2 x 1.01 g/mol (for hydrogen) + 1 x 16.00 g/mol (for oxygen) = 18.02 g/mol
The mass of 1.000 kg of water is:
m = 1.000 kg x 1000 g/kg = 1000 g
So, the number of moles of water is:
n = m/M = 1000 g / 18.02 g/mol = 55.49 mol
Therefore, there are 0.072 moles of calcium chloride and 55.49 moles of water present in the solution.
CaCl2 = 1 x 40.08 g/mol (for calcium) + 2 x 35.45 g/mol (for chlorine) = 110.98 g/mol
So, the number of moles of calcium chloride in 8.00 g is:
n = m/M = 8.00 g /110.98 g/mol = 0.072 mol
To calculate the number of moles of water, we can use its molar mass, which is:
H2O = 2 x 1.01 g/mol (for hydrogen) + 1 x 16.00 g/mol (for oxygen) = 18.02 g/mol
The mass of 1.000 kg of water is:
m = 1.000 kg x 1000 g/kg = 1000 g
So, the number of moles of water is:
n = m/M = 1000 g / 18.02 g/mol = 55.49 mol
Therefore, there are 0.072 moles of calcium chloride and 55.49 moles of water present in the solution.
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