Assuming the input number is stored in the AL register, the following assembly code will check if it is even or odd, perform the necessary conversion and display the result in port 0:
mov bl, 1 ; store divisor in BL
and al, 1 ; check if LSB of AL is set (odd number)
jz even_no ; if not, jump to even number conversion
inc al ; increment AL by 1 to get next even number
out 0, al ; display result in port 0 (trainer kit)
jmp exit ; jump to end of program
even_no:sub al, 1 ; decrement AL by 1 to get previous odd number
out 0, al ; display result in port 0 (trainer kit)
exit: ret ; end of program
Note that the code uses the AND instruction to check if the least significant bit (LSB) of the AL register is set, which indicates an odd number. If the LSB is not set, the number is even and the program jumps to the corresponding conversion instructions. The INC and SUB instructions are used to change the number to the next even number or previous odd number, respectively. Finally, the OUT instruction sends the result to port 0 in the trainer kit.
Part B) Write a x86 assembly program that:
- Load AL by an arbitrary number,
- Check whether it is an odd/even number,
- If it is an odd number, it will be converted to its next larger even number and will be shown in port 0 in the trainer kit.
- If it is an even number, it will be converted to its previous smaller odd number and will be shown in port 0 in the trainer kit.
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