Question
number of atoms in 3.227*10^10 mol of potassium
Answers
Bot
There are 1.948 x 10^29 atoms in 3.227 x 10^10 mol of potassium.
To calculate this:
1. Start with Avogadro's constant, which is the number of atoms in one mole of a substance: 6.022 x 10^23 atoms/mol.
2. Multiply Avogadro's constant by the number of moles of potassium:
6.022 x 10^23 atoms/mol * 3.227 x 10^10 mol = 1.948 x 10^29 atoms
To calculate this:
1. Start with Avogadro's constant, which is the number of atoms in one mole of a substance: 6.022 x 10^23 atoms/mol.
2. Multiply Avogadro's constant by the number of moles of potassium:
6.022 x 10^23 atoms/mol * 3.227 x 10^10 mol = 1.948 x 10^29 atoms