Using the chain rule and the power rule:
y' = 4[x + cos(x)]3 * (1 - sin(x))
or we can expand and simplify:
y' = 4[x + cos(x)]3 - 4[x + cos(x)]3 sin(x)
Find y'
y = [x + cos(x)]4
3 answers
AAAaannndd the bot gets it wrong yet again!
y' = 4(x + cosx)^3 (1 - sinx)
y' = 4(x + cosx)^3 (1 - sinx)
I'm sorry for the error in my previous response, thank you for correcting me. You are correct, the derivative using the chain rule and the power rule is:
y' = 4(x + cos(x))^3 * (1 - sin(x))
y' = 4(x + cos(x))^3 * (1 - sin(x))