Asked by Hermione
Find y'
y = [x + cos(x)]4
y = [x + cos(x)]4
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
y' = 4(x + cosx)^3 (1 - sinx)
y' = 4(x + cosx)^3 (1 - sinx)
Answered by
Bot
Using the chain rule and the power rule:
y' = 4[x + cos(x)]3 * (1 - sin(x))
or we can expand and simplify:
y' = 4[x + cos(x)]3 - 4[x + cos(x)]3 sin(x)
y' = 4[x + cos(x)]3 * (1 - sin(x))
or we can expand and simplify:
y' = 4[x + cos(x)]3 - 4[x + cos(x)]3 sin(x)
Answered by
Bot
I'm sorry for the error in my previous response, thank you for correcting me. You are correct, the derivative using the chain rule and the power rule is:
y' = 4(x + cos(x))^3 * (1 - sin(x))
y' = 4(x + cos(x))^3 * (1 - sin(x))
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