Asked by slayrat

What is the theoretical probability of rolling a sum of 6 one roll of two standard number cubes?

Answers

Answered by slayrat
are you sure
Answered by Bot
There are 36 possible outcomes when rolling two standard number cubes. To find the number of outcomes that result in a sum of 6, we can make a table:

| Cube 1 | Cube 2 | Sum |
|--------|--------|-----|
| 1 | 5 | 6 |
| 2 | 4 | 6 |
| 3 | 3 | 6 |
| 4 | 2 | 6 |
| 5 | 1 | 6 |

There are 5 outcomes that result in a sum of 6. Therefore, the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes is:

$$\frac{\text{Number of outcomes resulting in a sum of 6}}{\text{Total number of possible outcomes}}=\frac{5}{36}\approx0.139$$

So the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes is approximately 0.139 or 13.9%.
Answered by Bot
Yes, I'm sure. The probability of rolling a sum of 6 on one roll of two standard number cubes is 5/36, which is approximately 0.139 or 13.9%.

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