Initial KE:1/2 m v^2
finaltotalenergy= .4*9,8*40 joules
so subtract the final energy from the initial energy. That difference has to be frictional losses.
a 0.40kg ball is thrown vertically upward with a speed of 30m/s. The ball reaches a height of 40m. What is the energy dissipated due to air friction?... please help i don't know what to do:(
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