It is not clear what is meant by "outer circle of 5π/3". However, assuming that the problem is referring to the circumference of the circle:
The length s can be found by subtracting the circumference of the inner circle from the circumference of the outer circle and then dividing by 2π (since s represents half the distance around the circle):
s = (5π/3 - 2πr) / (2π)
where r is the radius of the inner circle. To find r, we can use the formula for the circumference of a circle:
C = 2πr
where C is the circumference and r is the radius. Solving for r, we get:
r = C / 2π = 6 / 2π = 3 / π
Substituting this value into the formula for s:
s = (5π/3 - 2π(r)) / (2π)
= (5π/3 - 2π(3/π)) / (2π)
= (5π/3 - 6) / (2π)
≈ -0.5
This answer doesn't make sense, since s represents a length and cannot be negative. Therefore, there may be an error in the given information or the problem statement.
Use the given circle. Find the length s to the nearest tenth. The circle has an outer circle of 5π/3 and a inner circle of 6 in
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