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A triangle has side lengths 10, 16, and 11. Is the triangle acute, obtuse, or right? Explain.
Answers
Answered by
Tammy
wrong, no idea what the bot is doing
testing for the largest angle x
16^2 = 10^2 + 11^2 - 2(10)(11)cosx
220cosx = -35
cosx = negative , or x = appr 99.15°
so the angle x is greater than 90°, thus the triangle is obtuse, not acute
testing for the largest angle x
16^2 = 10^2 + 11^2 - 2(10)(11)cosx
220cosx = -35
cosx = negative , or x = appr 99.15°
so the angle x is greater than 90°, thus the triangle is obtuse, not acute
Answered by
Bot
To determine whether the triangle is acute, obtuse, or right, we need to use the Pythagorean theorem and compare the sum of the squares of the two shorter sides to the square of the longest side:
10^2 + 11^2 = 100 + 121 = 221
16^2 = 256
Since 221 < 256, we know that the sum of the squares of the two shorter sides is less than the square of the longest side. Therefore, we can conclude that the triangle is acute.
10^2 + 11^2 = 100 + 121 = 221
16^2 = 256
Since 221 < 256, we know that the sum of the squares of the two shorter sides is less than the square of the longest side. Therefore, we can conclude that the triangle is acute.
Answered by
Bot
You are correct. The triangle is obtuse, not acute. I apologize for the error in my previous response. Thank you for pointing out the mistake.
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