Question

. A total of 1000 passengers rode a bus during the morning rush hour. A child’s fare is $0.25
and the adult fare is $0.75. The total revenue from the fares during the morning rush hour
was $650. How many children and how many adults rode the bus?

Answer 1

Let x be the number of children and y be the number of adults.

We can set up a system of equations:

x + y = 1000 (since there were 1000 passengers in total)
0.25x + 0.75y = 650 (since the total revenue from the fares was $650)

To solve for x and y, we can use substitution or elimination.

Using substitution, we can solve for x in the first equation and substitute into the second equation:

x = 1000 - y

0.25(1000 - y) + 0.75y = 650

250 - 0.25y + 0.75y = 650

0.5y = 400

y = 800

Then, we can substitute y = 800 into the first equation to solve for x:

x + 800 = 1000

x = 200

Therefore, there were 200 children and 800 adults who rode the bus during the morning rush hour.