Question
Camphor has a heat of combustion of5903.6 a sample of comfort having mass of 0.1204 gram is burn in a bond calorimetry the temperature increase by 2.28 degree centigrade calculate the heat capacity of the calorimetre
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First, we need to calculate the amount of heat produced by burning the camphor sample:
Q = m * ΔT * C
Where Q is the heat produced, m is the mass of camphor burned, ΔT is the temperature change of the calorimeter, and C is the heat capacity of the calorimeter.
m = 0.1204 g
ΔT = 2.28°C = 2.28 K
Q = 5903.6 J/g
So, Q = 0.1204 g * 2.28 K * C
Solving for C, we get:
C = Q / (m * ΔT) = 5903.6 J/g / (0.1204 g * 2.28 K)
C = 2071.5 J/K
Therefore, the heat capacity of the calorimeter is approximately 2071.5 J/K.
Q = m * ΔT * C
Where Q is the heat produced, m is the mass of camphor burned, ΔT is the temperature change of the calorimeter, and C is the heat capacity of the calorimeter.
m = 0.1204 g
ΔT = 2.28°C = 2.28 K
Q = 5903.6 J/g
So, Q = 0.1204 g * 2.28 K * C
Solving for C, we get:
C = Q / (m * ΔT) = 5903.6 J/g / (0.1204 g * 2.28 K)
C = 2071.5 J/K
Therefore, the heat capacity of the calorimeter is approximately 2071.5 J/K.