Question

a+c=120
5a+3c=458

Answer 1

To solve this system of equations, we can use either substitution or elimination. Here we will use elimination:

Multiplying the first equation by 5, we get:

5a + 5c = 600

Subtracting the second equation from this, we get:

2c = 142

c = 71

Substituting this into the first equation, we get:

a + 71 = 120

a = 49

Therefore, the solution is (a, c) = (49, 71).