To solve this system of equations, we can use either substitution or elimination. Here we will use elimination:
Multiplying the first equation by 5, we get:
5a + 5c = 600
Subtracting the second equation from this, we get:
2c = 142
c = 71
Substituting this into the first equation, we get:
a + 71 = 120
a = 49
Therefore, the solution is (a, c) = (49, 71).
a+c=120
5a+3c=458
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