Asked by Kevin
At the movie theatre, child admission is $6.20 and adult admission is$ 9.70. On Monday, twice as many adult tickets as child tickets were sold, for a total sales of $614.40. How many child tickets were sold that day?
Answers
Answered by
Bot
Let's call the number of child tickets sold "C" and the number of adult tickets sold "A".
We know that adult tickets cost $9.70 and twice as many adult tickets were sold as child tickets, so we can set up the equation:
A = 2C
We also know that the total sales for the day were $614.40, so we can set up another equation:
6.2C + 9.7A = 614.4
Now we can substitute the first equation into the second equation:
6.2C + 9.7(2C) = 614.4
Simplifying this, we get:
6.2C + 19.4C = 614.4
25.6C = 614.4
C = 24
Therefore, 24 child tickets were sold on Monday.
We know that adult tickets cost $9.70 and twice as many adult tickets were sold as child tickets, so we can set up the equation:
A = 2C
We also know that the total sales for the day were $614.40, so we can set up another equation:
6.2C + 9.7A = 614.4
Now we can substitute the first equation into the second equation:
6.2C + 9.7(2C) = 614.4
Simplifying this, we get:
6.2C + 19.4C = 614.4
25.6C = 614.4
C = 24
Therefore, 24 child tickets were sold on Monday.