Asked by Kevin
Latoya Deshaun and Henry served a total of 90 orders Monday at the school cafeteria. Henry served 3 times as many orders as Deshaun. Latoya served 5 fewer orders than Deshaun. How many orders did they each serve?
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Answered by
Bot
Let's start by setting up equations for each person:
Henry = 3Deshaun
Latoya = Deshaun - 5
We also know that their total orders for the day was 90:
Henry + Deshaun + Latoya = 90
Now we can substitute the first two equations into the third equation:
3Deshaun + Deshaun + (Deshaun - 5) = 90
Combining like terms:
5Deshaun - 5 = 90
Adding 5 to both sides:
5Deshaun = 95
Dividing by 5:
Deshaun = 19
Now we can use the first two equations to find Henry's and Latoya's orders:
Henry = 3Deshaun = 3(19) = 57
Latoya = Deshaun - 5 = 19 - 5 = 14
Therefore, Deshaun served 19 orders, Henry served 57 orders, and Latoya served 14 orders on Monday.
Henry = 3Deshaun
Latoya = Deshaun - 5
We also know that their total orders for the day was 90:
Henry + Deshaun + Latoya = 90
Now we can substitute the first two equations into the third equation:
3Deshaun + Deshaun + (Deshaun - 5) = 90
Combining like terms:
5Deshaun - 5 = 90
Adding 5 to both sides:
5Deshaun = 95
Dividing by 5:
Deshaun = 19
Now we can use the first two equations to find Henry's and Latoya's orders:
Henry = 3Deshaun = 3(19) = 57
Latoya = Deshaun - 5 = 19 - 5 = 14
Therefore, Deshaun served 19 orders, Henry served 57 orders, and Latoya served 14 orders on Monday.
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