Make the quote longer and more annoyed from this.
"Was there ever a time where you stopped talking for just ONE minute?"
9 answers
"Seriously, do you ever shut up? It's like you have verbal diarrhea and just can't help but spew meaningless words out of your mouth every chance you get. I swear, I can hardly get a word in edgewise with you around. Is it really so hard to just take a breath and let someone else speak for once? Honestly, it's exhausting trying to keep up with your incessant chatter."
Make it calm and reserved but still somewhat threatening.
"I'm sorry, but I must kindly ask you to cease the constant chatter. It's distracting and quite frankly, I find it rather displeasing. I prefer to converse in a more calm and collected manner, and your incessant talking is hindering my ability to do so. If you cannot control yourself and refrain from talking over me, I'm afraid I will have to excuse myself from this conversation."
\sum _{n-1}^{20}\:\left(5-n\right)
$\sum _{n-1}^{20}\:\left(5-n\right) = \left(5-(n-1)\right)+\left(5-(n-2)\right)+...+\left(5-19\right)+\left(5-20\right)$
$= 4+3+2+1+0+(-1)+(-2)+(-3)+(-4)+(-5)$
$= \sum_{i=1}^{10} i - \sum_{i=1}^{5} i$
$= \frac{10(10+1)}{2} - \frac{5(5+1)}{2}$
$= 55-15 = 40$
Therefore, the value of the sum is 40.
$= 4+3+2+1+0+(-1)+(-2)+(-3)+(-4)+(-5)$
$= \sum_{i=1}^{10} i - \sum_{i=1}^{5} i$
$= \frac{10(10+1)}{2} - \frac{5(5+1)}{2}$
$= 55-15 = 40$
Therefore, the value of the sum is 40.
\sum _{n-1}^{20}\:\left(5-n\right)
-220
-110
-95
110
-220
-110
-95
110
I'm sorry, I don't understand what you are asking. Please provide more context or clarify your question.
what is the sum of the series?
\sum _{n-1}^{20}\:\left(5-n\right)
-220
-110
-95
110
\sum _{n-1}^{20}\:\left(5-n\right)
-220
-110
-95
110
It seems that you are listing some numbers but it is not clear how they are related to the sum or the series in question. Without further information, it is not possible to provide an answer to your question. Please provide more details or specify your question more clearly.
1 answer