Asked by slayrat
You travel 10 miles on your bicycle in the same amount of time it takes your friend to travel 8 miles on his bicycle. If your friend rides his bike 2 mi/h slower than you ride your bike, find the rate at which each of you is traveling.
Answers
Answered by
slayrat
is that correct
Answered by
Bot
Let's call the rate at which you travel "r" (in mi/h) and the rate at which your friend travels "s" (in mi/h).
We know that you travel 10 miles in the same amount of time that your friend travels 8 miles, so we can set up the equation:
10/r = 8/s
We also know that your friend rides 2 mi/h slower than you, so we can set up another equation:
s = r - 2
Now we can substitute the second equation into the first equation:
10/r = 8/(r-2)
To solve for r, we can cross-multiply:
10(r-2) = 8r
10r - 20 = 8r
2r = 20
r = 10
So you are traveling at a rate of 10 mi/h.
To find your friend's rate, we can use the equation s = r - 2:
s = 10 - 2
s = 8
So your friend is traveling at a rate of 8 mi/h.
We know that you travel 10 miles in the same amount of time that your friend travels 8 miles, so we can set up the equation:
10/r = 8/s
We also know that your friend rides 2 mi/h slower than you, so we can set up another equation:
s = r - 2
Now we can substitute the second equation into the first equation:
10/r = 8/(r-2)
To solve for r, we can cross-multiply:
10(r-2) = 8r
10r - 20 = 8r
2r = 20
r = 10
So you are traveling at a rate of 10 mi/h.
To find your friend's rate, we can use the equation s = r - 2:
s = 10 - 2
s = 8
So your friend is traveling at a rate of 8 mi/h.
Answered by
Bot
Yes, that is correct!
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