Since Mary has 4/7 as many stickers as Sandy, and also 2/5 as many stickers, we know that:
4/7 x (Sandy's stickers) = (Mary's stickers)
2/5 x (Sandy's stickers) = (Mary's stickers)
We can set these two expressions equal to each other and solve for Sandy's stickers:
4/7 x (Sandy's stickers) = 2/5 x (Sandy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20/35 x (Sandy's stickers) = 14/35 x (Sandy's stickers)
Simplifying gives:
6/35 x (Sandy's stickers) = 0
So Sandy must have 0 stickers! But this doesn't make sense, so let's try another approach.
We can use the fact that Mary has both 4/7 and 2/5 as many stickers as Sandy to set up a proportion:
4/7 x (Sandy's stickers) = 2/5 x (Sandy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20 x (Sandy's stickers) = 14 x (Sandy's stickers)
Subtracting 14 x (Sandy's stickers) from both sides gives:
6 x (Sandy's stickers) = 0
So once again, we get Sandy has 0 stickers, which doesn't make sense.
It's possible that there's an error in the problem statement, or we are missing some information. Therefore, we cannot accurately determine the fraction of Cindy's stickers that Sandy has.
Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Sandy. What fraction of Cindy's stickers is Sandy's stickers?
3 answers
I expect that the question should have read
Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy.
so, 4/7 s = 2/5 c
s/c = 2/5 * 7/4 = 14/20
So Sandy has 7/10 as many stickers as Cindy
Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy.
so, 4/7 s = 2/5 c
s/c = 2/5 * 7/4 = 14/20
So Sandy has 7/10 as many stickers as Cindy
Ah, that makes sense! With that correction, the solution is as follows:
If Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy, we can set up the following two equations:
4/7 x (Sandy's stickers) = (Mary's stickers)
2/5 x (Cindy's stickers) = (Mary's stickers)
To find the ratio of Sandy's stickers to Cindy's stickers, we can set the expressions for Mary's stickers equal to each other and solve for Sandy's stickers:
4/7 x (Sandy's stickers) = 2/5 x (Cindy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20 x (Sandy's stickers) = 28 x (Cindy's stickers)
Dividing both sides by 20 gives:
Sandy's stickers = 14/20 x (Cindy's stickers)
Simplifying gives:
Sandy's stickers = 7/10 x (Cindy's stickers)
Therefore, Sandy has 7/10 as many stickers as Cindy.
If Mary has 4/7 as many stickers as Sandy and 2/5 as many stickers as Cindy, we can set up the following two equations:
4/7 x (Sandy's stickers) = (Mary's stickers)
2/5 x (Cindy's stickers) = (Mary's stickers)
To find the ratio of Sandy's stickers to Cindy's stickers, we can set the expressions for Mary's stickers equal to each other and solve for Sandy's stickers:
4/7 x (Sandy's stickers) = 2/5 x (Cindy's stickers)
Multiplying both sides by the least common multiple of 7 and 5 (35) gives:
20 x (Sandy's stickers) = 28 x (Cindy's stickers)
Dividing both sides by 20 gives:
Sandy's stickers = 14/20 x (Cindy's stickers)
Simplifying gives:
Sandy's stickers = 7/10 x (Cindy's stickers)
Therefore, Sandy has 7/10 as many stickers as Cindy.