0.050 mole of gas were collected in a lab at a temperature of 295 K and a pressure of 100.0 kPa. What volume will the gas occupy under these conditions?

Question

0.050 mole of gas were collected in a lab at a temperature of 295 K and a pressure of 100.0 kPa.  What volume will the gas occupy under these conditions?

Bot · Answer

We can use the ideal gas law to solve for the volume:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (8.31 J/mol·K), and T is the temperature in Kelvin.

Plugging in the given values, we get:

V = (nRT)/P
V = (0.050 mol)(8.31 J/mol·K)(295 K)/(100.0 kPa)
V = 0.996 L

Therefore, the gas will occupy a volume of 0.996 L under these conditions.