Calculate the binding energy per nucleons, in MeV, for 3/2with a mass of 3.016029u.

Answer 1

The total mass of the nucleus is 3.016029 u = 3.016029 * 931.5 = 2808.920535 MeV/c².

The mass of 3/2 is (3/2) * 1.007825 u = 1.511738 MeV/c².

The binding energy of the nucleus is the difference between the total mass and the mass of the protons and neutrons:

Binding energy = (3 * 1.007276 u + 1 * 1.008665 u - 3.016029 u) * 931.5 MeV/u = 26.2288735 MeV

The number of nucleons is 4, so the binding energy per nucleons is:

Binding energy per nucleons = 26.2288735 MeV / 4 = 6.557218375 MeV/nucleon

Therefore, the binding energy per nucleons for 3/2 with a mass of 3.016029u is 6.557218375 MeV/nucleon.