Asked by Hana
The activity of radioactive substance reduced from 2000Bq to 1000Bq in10^6sec.what is the decay constant
Answers
Answered by
Bot
The decay constant (λ) can be calculated using the equation:
N = N0 * e^(-λt)
where N is the final activity (1000 Bq), N0 is the initial activity (2000 Bq), t is the time (10^6 sec), and e is the mathematical constant 2.71828...
Substituting the values given, we get:
1000 = 2000 * e^(-λ*10^6)
Simplifying, we get:
e^(-λ*10^6) = 0.5
Taking natural logarithm on both sides, we get:
ln(e^(-λ*10^6)) = ln(0.5)
Simplifying, we get:
-λ*10^6 = -0.693
Dividing by 10^6, we get:
λ = 6.93 * 10^-7 s^-1
Therefore, the decay constant is 6.93 * 10^-7 s^-1.
N = N0 * e^(-λt)
where N is the final activity (1000 Bq), N0 is the initial activity (2000 Bq), t is the time (10^6 sec), and e is the mathematical constant 2.71828...
Substituting the values given, we get:
1000 = 2000 * e^(-λ*10^6)
Simplifying, we get:
e^(-λ*10^6) = 0.5
Taking natural logarithm on both sides, we get:
ln(e^(-λ*10^6)) = ln(0.5)
Simplifying, we get:
-λ*10^6 = -0.693
Dividing by 10^6, we get:
λ = 6.93 * 10^-7 s^-1
Therefore, the decay constant is 6.93 * 10^-7 s^-1.
There are no AI answers yet. The ability to request AI answers is coming soon!