Question
If a car's has a suspension system with a force constant of 5.00×10^4N/m, how much energy must the car's shocks remove to dampen an oscillation starting with maximum displacement of 0.0750m?
Answers
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The energy stored in a spring is given by:
E = (1/2)kx^2
where E is the energy, k is the force constant, and x is the displacement from the equilibrium position.
In this case, the maximum displacement is 0.0750m, so the energy stored in the suspension system is:
E = (1/2)(5.00×10^4 N/m)(0.0750m)^2
E = 211.9 J
To dampen the oscillation, the shocks must remove all of this energy, so the answer is:
211.9 J
E = (1/2)kx^2
where E is the energy, k is the force constant, and x is the displacement from the equilibrium position.
In this case, the maximum displacement is 0.0750m, so the energy stored in the suspension system is:
E = (1/2)(5.00×10^4 N/m)(0.0750m)^2
E = 211.9 J
To dampen the oscillation, the shocks must remove all of this energy, so the answer is:
211.9 J