In Young's double slit experiment, the slit are separated by 0.28mm and the screen is placed 1.4m away . the distance between the central bright fringes is measured to be 1.2cm .determine the wavelength of light used in the experiment?

Answer 1

We can use the formula:

λ = (d * y) / D

where λ is the wavelength of light, d is the distance between the slit (0.28mm), y is the distance between the central bright fringe and the first bright fringe on either side (0.6cm or 0.006m), and D is the distance between the slit and the screen (1.4m).

Plugging in the values, we get:

λ = (0.28 * 0.006) / 1.4
= 0.0000012 m or 1.2 x 10^-6 m

Therefore, the wavelength of light used in the experiment is 1.2 x 10^-6 meters or 1200 nanometers.