For each of the following find a point on each line.

Question

4x+3y-12=0

Answer 1

To find a point on the line 4x + 3y - 12 = 0, we can let x = 0 and solve for y:

4(0) + 3y - 12 = 0
3y = 12
y = 4

So the point (0,4) is on the line. We could also let y = 0 and solve for x:

4x + 3(0) - 12 = 0
4x = 12
x = 3

So the point (3,0) is also on the line.