First, we need to calculate the kinetic energy of the bowling ball rolling at 16 mph and 14 mph.
The formula for kinetic energy is KE = 1/2mv^2, where m is the mass of the object and v is its velocity.
At 16 mph or 7.1 m/s:
KE = 1/2 * 6 kg * (7.1 m/s)^2
KE = 151.83 J
At 14 mph or 6.2 m/s:
KE = 1/2 * 6 kg * (6.2 m/s)^2
KE = 108.72 J
The difference in kinetic energy is:
ΔKE = KE (16 mph) - KE (14 mph)
ΔKE = 151.83 J - 108.72 J
ΔKE = 43.11 J
Therefore, the bowling ball has 43.11 J more kinetic energy when rolling at 16 mph compared to rolling at 14 mph.
How much more kinetic energy does a 6 kg bowling ball have when it is rolling at 16 mph (7.1 m/s) then when it is rolling at 14 mph (6.2 m/s)?
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