Subtract.

Question

(4y^2-3y+1)-(-8y^3+3)

Answer 1

To subtract these polynomials, we need to distribute the negative sign to every term inside the parentheses:

4y^2 - 3y + 1 + 8y^3 - 3

Now we can combine like terms, starting with the highest degree of y:

8y^3 + 4y^2 - 3y + 1 - 3

Simplifying:

8y^3 + 4y^2 - 3y - 2

So the difference of (4y^2-3y+1)-(-8y^3+3) is 8y^3 + 4y^2 - 3y - 2.