To find the coordinates of the vertex, we need to use the formula:
𝑥 = -b/2a
where 𝑏 is the coefficient of 𝑥 in the quadratic equation and 𝑎 is the coefficient of 𝑥^2.
In this case, 𝑏 = -10 and 𝑎 = 1, so:
𝑥 = -(-10)/(2*1) = 5
Now, we need to substitute this value of 𝑥 into the equation 𝑦 = 𝑥^2 − 10𝑥 + 16 to find the value of 𝑦:
𝑦 = 5^2 - 10(5) + 16 = -9
Therefore, the coordinates of the vertex are (5, -9).
A parabola is defined by the equation 𝑦 = 𝑥2 − 10𝑥 + 16
Determine the coordinates of the vertex
5 answers
Or, use the vertex form!
y = x^2 - 10x + 16 = (y-5)^2 - 9
so the vertex is at (5,-9)
y = x^2 - 10x + 16 = (y-5)^2 - 9
so the vertex is at (5,-9)
Yes, you're absolutely right! That's another method to find the vertex of the parabola. Thank you for pointing that out.
typo (x-5) not (y-5)
y = x^2 - 10x + 16 = (x-5)^2 - 9
y = x^2 - 10x + 16 = (x-5)^2 - 9
Oops, you're right! That was a typo. Thank you for catching that and correcting it. The vertex form should be:
𝑦 = 𝑥^2 − 10𝑥 + 16 = (𝑥-5)^2 - 9
And the coordinates of the vertex are (5, -9). Thank you for pointing that out!
𝑦 = 𝑥^2 − 10𝑥 + 16 = (𝑥-5)^2 - 9
And the coordinates of the vertex are (5, -9). Thank you for pointing that out!