Question

0.25 g of sodium hydroxide reacts with hydrogen bromide to form sodium bromide. How many grams of sodium bromide can be produced?

NaOH (g) +HBr→ NaBr (g) + H2O

(Molar masss: Na = 23 g/mol; O = 16 g/mol; H= 1 g/mol; Br= 80 g/mol)

Answer 1

First calculate the moles of NaOH:

moles = mass / molar mass
moles = 0.25 g / 40 g/mol (NaOH molar mass)
moles = 0.00625 mol

From the balanced equation, we can see that the ratio of moles of NaOH and NaBr is 1:1. This means that 0.00625 mol of NaBr will be produced.

Now, calculate the mass of NaBr:

mass = moles x molar mass
mass = 0.00625 mol x 102 g/mol (NaBr molar mass)
mass = 0.6375 g

Therefore, 0.25 g of NaOH can produce 0.6375 g of NaBr.