To find the 𝑥-intercepts of the parabola, we set y = 0 and solve for x:
0 = x^2 - 10x + 16
We can factor the quadratic as (x-2)(x-8) = 0, or use the quadratic formula:
x = [10 ± √(10^2 - 4(1)(16))] / 2
x = [10 ± √36] / 2
x = 5 ± 3
So the 𝑥-intercepts of the parabola are at x = 2 and x = 8.
A parabola is defined by the equation 𝑦 = 𝑥2 − 10𝑥 + 16 b)
Identify the 𝑥-intercepts of the parabola
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