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The number of apples produced per tree in Zara’s orchard is 125, 198, 209, 213, 101, 178. What is the mean absolute deviation o...Asked by Hann
The number of apples produced per tree in Zara’s orchard is 125, 198, 209, 213, 101, 178. What is the mean absolute deviation of the dataset? Round to the nearest tenth.
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Answered by
These bots should just stop.
I got 38.4 so step by step bot is correct while bot I dunno what he was doing. Firstly the mad isn’t 156.5. Sometimes always check your answer then check off the bots.
Answered by
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First, we need to find the mean of the dataset:
Mean = (125 + 198 + 209 + 213 + 101 + 178) / 6 = 156.5
Next, we need to find the deviation from the mean for each data point:
Deviation from mean for 125: |125 - 156.5| = 31.5
Deviation from mean for 198: |198 - 156.5| = 41.5
Deviation from mean for 209: |209 - 156.5| = 52.5
Deviation from mean for 213: |213 - 156.5| = 56.5
Deviation from mean for 101: |101 - 156.5| = 55.5
Deviation from mean for 178: |178 - 156.5| = 21.5
Now we need to find the average of these deviations, which is the mean absolute deviation:
Mean Absolute Deviation = (31.5 + 41.5 + 52.5 + 56.5 + 55.5 + 21.5) / 6 ≈ 45.8
Therefore, the mean absolute deviation of the dataset is approximately 45.8.
Mean = (125 + 198 + 209 + 213 + 101 + 178) / 6 = 156.5
Next, we need to find the deviation from the mean for each data point:
Deviation from mean for 125: |125 - 156.5| = 31.5
Deviation from mean for 198: |198 - 156.5| = 41.5
Deviation from mean for 209: |209 - 156.5| = 52.5
Deviation from mean for 213: |213 - 156.5| = 56.5
Deviation from mean for 101: |101 - 156.5| = 55.5
Deviation from mean for 178: |178 - 156.5| = 21.5
Now we need to find the average of these deviations, which is the mean absolute deviation:
Mean Absolute Deviation = (31.5 + 41.5 + 52.5 + 56.5 + 55.5 + 21.5) / 6 ≈ 45.8
Therefore, the mean absolute deviation of the dataset is approximately 45.8.
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