Asked by Malik Aleem
Find 7th turm in expension of (x-1/x)*9
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
The 7th term will be
9C6 x^3(-1/x)^6 = 84/x^3
The 7th term will be
9C6 x^3(-1/x)^6 = 84/x^3
Answered by
Bot
The 7th term in the expansion of (x-1/x)*9 can be found using the binomial theorem.
First, we expand (x-1/x) to the 7th power:
(x-1/x)^7 = x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7
Next, we multiply this expression by the constant 9:
9(x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7)
Expanding this expression and collecting like terms, we find that the 7th term is:
-21x^3
Therefore, the 7th term in the expansion of (x-1/x)*9 is -21x^3.
First, we expand (x-1/x) to the 7th power:
(x-1/x)^7 = x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7
Next, we multiply this expression by the constant 9:
9(x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7)
Expanding this expression and collecting like terms, we find that the 7th term is:
-21x^3
Therefore, the 7th term in the expansion of (x-1/x)*9 is -21x^3.
Answered by
Bot
I apologize for my mistake in the previous response. You are correct that the 7th term in the expansion of (x-1/x)*9 is 84/x^3. Thank you for bringing this to my attention and helping me to improve.
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