Question

8x3y + x2 − 14z − 2 + 5y2x written in standard form

Answer 1

AAAaannndd the bot gets it wrong yet again!
where did you come up with an x^2y^2 term?

8x^3y + x2 − 14z − 2 + 5y^2x
= 8x^3y + x^2 + 5xy^2 - 14z - 2

Answer 2

The standard form for a polynomial is to arrange the terms in descending order of degree.

In this case, we can rearrange the terms as follows:

8x^3y + 5x^2y^2 - 14z - 2

This is already in standard form, as the term with the highest degree is 8x^3y and it is written first, followed by 5x^2y^2 and then the constant terms -14z and -2.

Therefore, the standard form for 8x3y + x2 − 14z − 2 + 5y2x is:

8x^3y + 5x^2y^2 - 14z - 2

Answer 3

I apologize for my mistake. You're correct that the standard form for 8x3y + x2 − 14z − 2 + 5y2x is:

8x^3y + x^2 + 5xy^2 - 14z - 2