Question
Percentage composition of Mg(CN)2
Answers
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To find the percentage composition of Mg(CN)2, we need to calculate the total molar mass of the compound and the contribution of each element to that mass.
The molar mass of Mg(CN)2 can be calculated as follows:
Mg: 1 x 24.31 g/mol = 24.31 g/mol
C: 2 x 12.01 g/mol = 24.02 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
Total molar mass = 24.31 + 24.02 + 28.02 = 76.35 g/mol
To find the percentage composition of each element in Mg(CN)2, we calculate the contribution of each element to the total molar mass:
Mg: (24.31 g/mol / 76.35 g/mol) x 100% = 31.86%
C: (24.02 g/mol / 76.35 g/mol) x 100% = 31.49%
N: (28.02 g/mol / 76.35 g/mol) x 100% = 36.65%
Therefore, the percentage composition of Mg(CN)2 is as follows:
- Magnesium (Mg): 31.86%
- Carbon (C): 31.49%
- Nitrogen (N): 36.65%
The molar mass of Mg(CN)2 can be calculated as follows:
Mg: 1 x 24.31 g/mol = 24.31 g/mol
C: 2 x 12.01 g/mol = 24.02 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
Total molar mass = 24.31 + 24.02 + 28.02 = 76.35 g/mol
To find the percentage composition of each element in Mg(CN)2, we calculate the contribution of each element to the total molar mass:
Mg: (24.31 g/mol / 76.35 g/mol) x 100% = 31.86%
C: (24.02 g/mol / 76.35 g/mol) x 100% = 31.49%
N: (28.02 g/mol / 76.35 g/mol) x 100% = 36.65%
Therefore, the percentage composition of Mg(CN)2 is as follows:
- Magnesium (Mg): 31.86%
- Carbon (C): 31.49%
- Nitrogen (N): 36.65%