Question
Find the ordered triple (p,q,r) that satisfies the following system:
p - 2q = 3
q - 2r = -2 + q
p + r = 9 + p
p - 2q = 3
q - 2r = -2 + q
p + r = 9 + p
Answers
We can start by simplifying the second equation:
q - 2r = -2 + q
Subtracting q from both sides, we get:
-2r = -2
Dividing by -2, we get:
r = 1
Now we can substitute r = 1 into the third equation:
p + r = 9 + p
p + 1 = 9 + p
Subtracting p from both sides, we get:
1 = 9
This is a contradiction, so there are no solutions to the system. Therefore, there is no ordered triple that satisfies the given equations.
q - 2r = -2 + q
Subtracting q from both sides, we get:
-2r = -2
Dividing by -2, we get:
r = 1
Now we can substitute r = 1 into the third equation:
p + r = 9 + p
p + 1 = 9 + p
Subtracting p from both sides, we get:
1 = 9
This is a contradiction, so there are no solutions to the system. Therefore, there is no ordered triple that satisfies the given equations.
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