Asked by Thatgirl

Given the following dataset, what are the extremes?
58, 32, 8, 25, 13, 12, 3, 11, 22, 10(1 point)
Answered by Thatgirl
Given the following dataset, what is the first quartile? Round to the nearest tenth if necessary.
42, 82, 67, 34, 54, 62, 17, 47, 56, 18, 20
Answered by Thatgirl
The amounts of rainfall measured in inches in downtown Los Angeles during the six rainy seasons from 2000 to 2006 are given as a dataset.

15.56, 4.16, 10.38, 8.61, 26.51, 10.89

Find the range of this dataset.

(1 point)
Answered by Thatgirl
The average temperatures in December in Washington, D.C., from 1993 to 1998 are given as a dataset.

38.1, 44.2, 35.6, 43.0, 41.0, 44.4

Find the interquartile range of the dataset.
Answered by Thatgirl
Identify the first quartile in the following dataset:
5, 7, 9, 4, 3, 2, 1, 0, 11, 12, 6, 3, 4, 3, 2, 6(1 point)
Responses

6.5
6.5

2.5
2.5

4
4

0
0
Answered by Thatgirl
Identify the third quartile in the following dataset:
53.3, 46.9, 48.1, 49.7, 52.1, 47.5, 47.2, 45.5(1 point)
Responses

53.3
53.3

47.8
47.8

47.05
47.05

50.9
50.9
Answered by Thatgirl
Find the range of the given data set.

51, 13, 98, 42, 76, 28

(1 point)
Responses

98
98

85
85

13
13

23
Answered by Thatgirl
Find the interquartile range of the given dataset.

11, 13, 22, 17, 14, 21, 27, 15

(1 point)
Responses

8
8

21.5
21.5

13.5
13.5

6.5
Answered by Thatgirl
The heights in inches of six basketball players at a local high school are given as a dataset.

70, 78, 74, 82, 68, 75

Find the range and the interquartile range of the dataset.

(1 point)
Responses

The range is 14, and the interquartile range is 8.
The range is 14, and the interquartile range is 8.

The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.

The range is 14, and the interquartile range is 4.5.
The range is 14, and the interquartile range is 4.5.

The range is 14, and the interquartile range is 74.5.
Answered by Bot
The lowest extreme is 3 and the highest extreme is 58.
Answered by Bot
To find the first quartile, we need to arrange the data in order from lowest to highest:

17, 18, 20, 34, 42, 47, 54, 56, 62, 67, 82

There are a couple of methods for finding the first quartile, but one common way is to take the median of the lower half of the data. In this case, the lower half consists of:

17, 18, 20, 34, 42

The median of this lower half is 20.

Therefore, the first quartile is 20.
Answered by Bot
To find the range, we first need to find the highest and lowest values in the dataset.

Highest value = 26.51

Lowest value = 4.16

Range = highest value - lowest value

Range = 26.51 - 4.16

Range = 22.35

Therefore, the range of the dataset is 22.35 inches.
Answered by Bot
To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).

To find Q1:

1. Put the data in order from least to greatest:

35.6, 38.1, 41.0, 43.0, 44.2, 44.4

2. Find the median of the lower half of the data:

35.6, 38.1, 41.0

Median = 38.1

Q1 = 38.1

To find Q3:

1. Put the data in order from least to greatest:

35.6, 38.1, 41.0, 43.0, 44.2, 44.4

2. Find the median of the upper half of the data:

43.0, 44.2, 44.4

Median = 44.2

Q3 = 44.2

Now that we know Q1 and Q3, we can find the IQR:

IQR = Q3 - Q1

IQR = 44.2 - 38.1

IQR = 6.1

Therefore, the interquartile range of the dataset is 6.1.
Answered by Bot
To find the first quartile, we need to arrange the data in order from lowest to highest:

0, 1, 2, 2, 3, 3, 3, 4, 4, 5, 6, 6, 7, 9, 11, 12

There are different methods for finding the first quartile, but one common way is to take the median of the lower half of the data. In this case, the lower half consists of:

0, 1, 2, 2, 3, 3, 3, 4

The median of this lower half is (2+3)/2 = 2.5.

Therefore, the first quartile is 2.5.
Answered by Bot
To find the third quartile, we need to arrange the data in order from lowest to highest:

45.5, 46.9, 47.2, 47.5, 48.1, 49.7, 52.1, 53.3

There are different methods for finding the third quartile, but one common way is to take the median of the upper half of the data. In this case, the upper half consists of:

48.1, 49.7, 52.1, 53.3

The median of this upper half is (49.7+52.1)/2 = 50.9.

Therefore, the third quartile is 50.9.
Answered by Bot
To find the range, we first need to find the highest and lowest values in the dataset.

Highest value = 98

Lowest value = 13

Range = highest value - lowest value

Range = 98 - 13

Range = 85

Therefore, the range of the dataset is 85.
Answered by Bot
To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).

To find Q1:

1. Put the data in order from least to greatest:

11, 13, 14, 15, 17, 21, 22, 27

2. Find the median of the lower half of the data:

11, 13, 14, 15

Median = (13+14)/2 = 13.5

Q1 = 13.5

To find Q3:

1. Put the data in order from least to greatest:

11, 13, 14, 15, 17, 21, 22, 27

2. Find the median of the upper half of the data:

21, 22, 27

Median = (22+21)/2 = 21.5

Q3 = 21.5

Now that we know Q1 and Q3, we can find the IQR:

IQR = Q3 - Q1

IQR = 21.5 - 13.5

IQR = 8

Therefore, the interquartile range of the dataset is 8.
Answered by Bot
To find the range, we first need to find the highest and lowest values in the dataset.

Highest value = 82

Lowest value = 68

Range = highest value - lowest value

Range = 82 - 68

Range = 14

To find the interquartile range (IQR), we need to first find the first quartile (Q1) and third quartile (Q3).

To find Q1:

1. Put the data in order from least to greatest:

68, 70, 74, 75, 78, 82

2. Find the median of the lower half of the data:

68, 70, 74

Median = 70

Q1 = 70

To find Q3:

1. Put the data in order from least to greatest:

68, 70, 74, 75, 78, 82

2. Find the median of the upper half of the data:

75, 78, 82

Median = 78

Q3 = 78

Now that we know Q1 and Q3, we can find the IQR:

IQR = Q3 - Q1

IQR = 78 - 70

IQR = 8

Therefore, the range of the dataset is 14 and the interquartile range is 8.