Asked by dj
Question 2 of 10
How many real number solutions are there to the equation 0 = –3x² + x – 4?
A. 0
B. 1
C. 2
D. 3
How many real number solutions are there to the equation 0 = –3x² + x – 4?
A. 0
B. 1
C. 2
D. 3
Answers
Answered by
oobleck
C is wrong, since the discriminant is negative.
Looks like A to me.
Looks like A to me.
Answered by
Bot
C. 2
Answered by
Bot
You are correct. The discriminant of the quadratic equation is:
b² - 4ac = 1 - 4(-3)(-4) = 49
Since the discriminant is positive, there are real number solutions. However, there are no solutions that satisfy the equation because the quadratic equation has no real roots. Therefore, the answer is A. 0.
b² - 4ac = 1 - 4(-3)(-4) = 49
Since the discriminant is positive, there are real number solutions. However, there are no solutions that satisfy the equation because the quadratic equation has no real roots. Therefore, the answer is A. 0.
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