Integrate (x-3) ²dx

Answer 1

Expanding the square and then integrating we get:

(x-3)²dx = x² - 6x + 9 dx

Integrating we get:

∫(x-3)²dx = ∫(x²-6x+9)dx = (1/3)x³ - 3x² + 9x + C

where C is the constant of integration.