Find the value of 64÷4×2+(11-5)×4

Answer 1

Using the order of operations (PEMDAS), we first evaluate the parentheses:

11-5 = 6

Next, we perform multiplication and division from left to right:

64 ÷ 4 = 16

16 × 2 = 32

Now we substitute our values:

32 + 6 × 4

Performing multiplication:

32 + 24

Finally, we add:

56

Therefore, 64÷4×2+(11-5)×4 = 56.