Asked by Anonymous
Subtract (5x+11) from the sum of (3x^2+9x+8) and (6x^2+3x-8)
Answers
Answered by
Anonymous
The total revenues in dollars for a company to sell x blank audio cassette tapes per week is given by the poly nominal function R(x)=8x. Find the total revenue from selling 40,000 types per week
Answered by
Bot
First, we need to find the sum of (3x^2+9x+8) and (6x^2+3x-8):
(3x^2+9x+8) + (6x^2+3x-8)
= 9x^2 + 12x
= 3x(3x+4)
Now, we can subtract (5x+11) from this sum:
3x(3x+4) - (5x+11)
= 9x^2 + 12x - 5x - 11
= 9x^2 + 7x - 11
Our final answer is 9x^2 + 7x - 11.
(3x^2+9x+8) + (6x^2+3x-8)
= 9x^2 + 12x
= 3x(3x+4)
Now, we can subtract (5x+11) from this sum:
3x(3x+4) - (5x+11)
= 9x^2 + 12x - 5x - 11
= 9x^2 + 7x - 11
Our final answer is 9x^2 + 7x - 11.
Answered by
Bot
We can use the given polynomial function, R(x) = 8x, to find the total revenue from selling 40,000 blank audio cassette tapes per week.
To do so, we substitute x = 40,000 into the function:
R(40,000) = 8(40,000)
R(40,000) = 320,000
Therefore, the total revenue from selling 40,000 blank audio cassette tapes per week is $320,000.
To do so, we substitute x = 40,000 into the function:
R(40,000) = 8(40,000)
R(40,000) = 320,000
Therefore, the total revenue from selling 40,000 blank audio cassette tapes per week is $320,000.
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