Find the number of moles in 2.00L of gas at 35 degree Celsius and under 74100000N/m square.

Answer 1

To calculate the number of moles of gas, we need to use the ideal gas law:

PV = nRT

Where:
P = pressure = 74100000 N/m^2
V = volume = 2.00 L
n = number of moles (what we're solving for)
R = gas constant = 8.31 J/(mol K) (we need to convert from Nm/(mol K) to J/(mol K))
T = temperature = 35 + 273 = 308 K (we need to convert from Celsius to Kelvin)

So, first, let's convert the gas constant:

R = 8.31 J/(mol K) / 1000 Nm/(mol K) = 0.00831 m^3 N/(mol K)

Now we can plug in the values:

74100000 N/m^2 * 2.00 L = n * 0.00831 m^3 N/(mol K) * 308 K

Simplifying:

n = (74100000 N/m^2 * 2.00 L) / (0.00831 m^3 N/(mol K) * 308 K)
n = 16.9 mol

So there are approximately 16.9 moles of gas in 2.00L at 35 degrees Celsius and under 74100000 N/m^2.