A special gas mixture is used in bacterial growth chambers which contains 5.00% by mass of CO2 and 95.0% O2. If the mole fraction of CO2 and O2 in the mixture is 0.0998 and 0.2340, respectively. What is the partial pressure in atmospheres of O2 and CO2 gases at a total pressure of 0.6880 atm?

CO2 = 0.0687 atm and O2 = 0.161 atm

CO2 = 0.000494 atm and O2 = 0.2223 atm

CO2 = 0.6536 atm and O2 = 0.0344 atm

CO2 = 0.0998 atm and O2 = 0.2340 atm

1 answer

The correct answer is: CO2 = 0.0687 atm and O2 = 0.161 atm.

To solve this problem, we first need to find the partial pressure of each gas in the mixture. We can use the mole fraction and total pressure to do this.

Partial pressure of CO2 = 0.0998 x 0.6880 atm = 0.0687 atm

Partial pressure of O2 = 0.2340 x 0.6880 atm = 0.161 atm

Therefore, the correct answer is option A: CO2 = 0.0687 atm and O2 = 0.161 atm.